Xiao Ming read a mini-novel in three days. On the first day, he read more than a quarter of the entire book and six pages. On the second day, he read half of the entire book. On the third day, he read twice as many pages as the first day. According to the description of the title, Xiaoming read 1/4 of the book on the first day, which was 1/4 + 6/100 = 17/100 = 1/5. Therefore, Xiao Ming read about one-fifth of the book on the first day. The next day, Xiao Ming read half of the book. Therefore, Xiao Ming read 1/2 × 1/2 = 1/4 of the book the next day. On the third day, Xiao Ming read twice the number of the first day, which was 1/5 × 2 = 4/15. Therefore, Xiao Ming read about 4/15 of the book on the third day. As Xiao Ming read for a total of 3 days, the total number of pages in the book is: Total pages = Day 1 pages + Day 2 pages + Day 3 pages = 1/5 + 1/4 + 4/15 = 9/10 Therefore, the total number of pages in the novel was nine.
If Xiaoming reads 72 pages in the first 4 days, then Xiaoming's total page count in the first 4 days is 72 pages. Reading 29 pages every day for the next 6 days would mean that the total number of pages for the next 6 days would be 29 pages x 6 days = 171 pages. Therefore, Little Ming's total page count in the last six days was 171 pages. Little Ming read 171 pages per day for the next 6 days, 6 days = 27 pages. Therefore, Xiao Ming read an average of 27 pages a day.
Xiao Ming read a book on the first day, he read 1/6 of the whole book, the second day, he read 24 pages, the third day, he read the total number of pages in the previous two days If he read 24 pages the next day, he would read (24 div6) = 4 pages the next day. The rest of the books had 5/6 pages. Xiaoming read 1/6 pages on the first day, so he read (5/6 div1/6) = 30 pages on the first day. Xiao Ming's remaining book had 1/6 pages. The number of pages he read the next day was 4 + 30 = 34. Xiao Ming's remaining book had 1/6 pages. The number of pages he read on the third day was 34 + 24 = 58. Therefore, on the third day, Xiao Ming read the entire book's 58 + 6 = 9 pages.
How many pages are there in this book? According to the title, Xiaoming read 10% of the book on the first day, which was 10% of the book divided by 100% = 1/10 pages. Xiao Ming read 35% of the book the next day, which was 35% of the book divided by 100% = 035 pages. Xiao Ming read 44 pages of the book on the third day, so the number of pages in the book can be calculated by the following formula: 1 ÷ (1/10 + 035 + 1/10) = 44 Solve the equation: Number of pages in the book = 44 × 100%/(1 + 035 + 1) = 3520 Therefore, this book had a total of 3520 pages.
Xiao Ming read a novel on the first day and read 1/8 of the entire book with 21 pages more. On the second day, he read 1/6 of the entire book with 4 pages less, leaving 102 pages unread. We can use the following formula to calculate the remaining pages: Remaining pages = total pages-number of pages viewed Putting the known information into the formula, he obtained: Remaining pages = 102 pages Therefore, Xiao Ming read 1/6 of the book on the second day, leaving 102 pages.
Xiao Ming read a book for the first 4 days and read 15 pages, then read 6 pages every day for 5 days. We can use the following formula to calculate the average number of pages seen per day: Average number of pages read per day = total number of pages/days Substituting the total number of pages and the number of days into the formula, we get: Average number of pages read per day = 15 pages/4 days = 3 pages/day Therefore, Xiao Ming read an average of three pages a day.
Xiao Ming planned to read 36 pages a day, but in fact, he read 500 pages in 12 days. 500 pages/12 days = 40 pages/day Because Xiao Ming reads 36 pages a day, the actual number of pages should be 40 pages more than the plan: 40 pages/day- 36 pages/day = 4 pages/day Therefore, Xiao Ming actually read four more pages of novels every day.
小明看一本故事书第一天看了30页是全书总页数的五分之三那么第一天看了全书的 $\frac{30}{5}$ 页. 第二天看了全书的十分之一即第二天看了 $\frac{1}{10}$ 页. 因此第二天看了 $\frac{30}{5} \cdot \frac{1}{10} = \frac{3}{5}$ 页. 所以小明在第二天看了 $\frac{3}{5}$ 页也就是全书的 $\frac{3}{5}$ 页.
The number of pages in this book is 256. Xiaoming reads 20 pages a day, so he can read 24 pages a day. In three days, he could finish reading a book with 256 pages. Therefore, Xiao Ming read a total of 256 pages x 3 = 768 pages in three days. After reading these 768 pages, Little Ming still had 768 pages- 256 pages = 512 pages to read. Little Ming read 512 pages/ 20 pages = 26 days. Therefore, this book had a total of 256 + 512 = 768 pages.
Xiao Ming plans to read a novel every few days. If he reads 60 pages a day, he can finish it five days earlier. If he reads 40 pages a day, he will finish it three days later. Calculating how much faster reading 60 pages a day was than reading 40 pages a day: Reading 60 pages a day is better than reading 40 pages a day, reading 40 pages per hour, 60 pages = 067 hours Therefore, the total time Little Ming needed was: 1/067 = 1667(hours) 5 days ago 1667/067 = 28(hours) Days of delay Therefore, Xiao Ming needed 28 hours to finish reading this novel, which was longer than expected. Next, we can calculate the ratio of reading 60 pages a day to reading 40 pages a day, reading 40 pages per hour, reading 60 pages = 067 hours 's progress: Reading 60 pages a day is better than reading 40 pages a day. Reading 60 pages per hour/40 pages = 15 hours Therefore, the total time Little Ming needed was: 1 × 15 = 0667(hour) 5 days ago 0667/15 = 04(hours) Days of delay Therefore, Xiaoming needed four hours to finish reading this novel, which was shorter than the estimated time. To sum up, Xiaoming plans to read a novel every few days. If he reads 60 pages a day, he can finish it five days earlier. If he reads 40 pages a day, he will finish it three days later. If reading 60 pages a day was faster than reading 40 pages a day, reading 40 pages per hour, reading 60 pages per hour = 067 hours, the total time required was 1667 hours; if reading 60 pages a day was slower than reading 40 pages a day, reading 60 pages per hour, reading 60 pages per hour = 15 hours, the total time required was 0667 hours.
Suppose the book has a total of x pages, and Chen Ming has read a total of y pages in these seven days: - Chen Ming read 11*3=33 pages in the first three days - In the next three days, Chen Ming read a total of 18*3=54 pages - In seven days, Chen Ming read a total of y*7=497 pages Therefore, Chen Ming read an average of 497/7=74 pages a day in the past seven days.