The number of pages that Xiaoming reads on the first day is 20% of the whole book. The number of pages that he reads on the second day is 20% of the remaining pages. The percentage of the number of pages that he reads on the second day can be calculated as follows: The number of pages that Xiaoming read on the first day was 20% of the entire book. In other words, the total number of pages that Xiaoming read was: Total pages = 20% × pages of the book = 02 × pages of the book The number of pages that Xiao Ming read the next day was 20% of the remaining pages. In other words, the total number of pages that Xiao Ming read was: Total pages = 20% x Remaining pages = 02 x Remaining pages Then, the percentage of the number of pages that Xiao Ming read the next day in the total number of pages in the book can be calculated as: The number of pages Xiao Ming read the next day divided by the total number of pages in the book × 100% = 02 divided by 08 × 100%= 25% Therefore, the number of pages that Xiao Ming read the next day accounted for about 25% of the total number of pages in the entire book.
Xiao Ming read 20% of the total number of pages on the first day of reading a book, which means that the total number of pages multiplied by 20% equals 20% of the total number of pages. On the second day, the ratio of pages read on the first day was 5:4, which meant that half of the total pages read on the second day was 25% of the total pages. Therefore, Xiao Ming read the total number of pages multiplied by 25% the next day, which was equal to the total number of pages multiplied by 5%. Divide the total number of pages by 5 to get the number of pages that Xiaoming read the next day divided by 5. That is, the total number of pages divided by 5 multiplied by 40% equals the total number of pages multiplied by 10%. Therefore, Xiao Ming read the total number of pages multiplied by 10% the next day, which was equal to the total number of pages multiplied by 5.
Xiao Ming read a story book and read a total of 38 pages in the first two days and 54 pages in the next three days. We can use the total number of pages to deduct the number of pages in the first two days and the next three days to get the average number of pages that Xiaoming reads every day. Total pages = 38 + 54 = 82 In the previous two days, he had read 38 pages, so the ratio of the number of pages read in the previous two days to the total number of pages was 38 pages/ 82 pages = 047875, which could be approximately expressed as 047875. In the next three days, a total of 54 pages were read. The ratio of the number of pages read in the next three days to the total number of pages was 54 pages/ 82 pages = 06667, which could be approximately expressed as 06667. Therefore, on average, Xiaoming reads 047875 × 2 + 06667 × 3 = 016533 × 2 + 023333 × 3 = 039167 × 2 + 050938 × 3 = 089715 × 2 + 010785 × 3 = 1575 × 2 + 0192 × 3 = 27533 every day, which is about 275. Therefore, Xiao Ming read an average of 275 pages a day.
Xiao Ming reads a novel. If he reads 35 pages a day, he will finish the whole book one day later than the stipulated date. If he reads 40 pages a day, he will read 5 pages less on the last day. We can set the total number of pages of the novel as x and the specified date as d, then the total number of pages that Xiaoming needs to read is x/35 + x/40 - 1. According to the question, Xiaoming needs to read d books, so there are: x/35 + x/40 - 1 = d Transferring the terms of the equation gave: x/100 = d Therefore, Xiao Ming needed to read 100 pages a day to finish the novel by the stipulated date. If you read 35 pages a day, you would need an extra two days to finish the novel. If you read 40 pages a day, you would need an extra three days to finish the novel. After considering all, Xiaoming needed to read 37 pages a day to finish the novel according to the stipulated date. On the last day, he had to read 5 pages less.
Suppose the book has a total of $n$pages, the number of pages read is $m$, and the number of unread pages is $n-m$. According to the question, the ratio of the number of pages read to the number of pages unread is two to three, and the following equations can be listed: $$ \begin{cases} m = 2(n-m) \\ m + 30 = n \end{cases} $$ Transforming the second equation into $n = 4m + 30$and replacing it into the first equation gives $2m = 30$. The solution is $m = 15$. So the book has a total of $n=50$pages, the number of pages read is $m=20$, and the number of unread pages is $n-m=30$.
Xiaoming reads a storybook for the first 4 days, reads 25 pages a day, then reads 40 pages a day, and reads for 6 days, just finishing it. How many pages does Xiaoming read on average every day? The number of pages in the storybook was fixed. The number of pages read in the first four days was 25 x 4 = 100 pages, and the remaining pages were 100 - 6 x 25 = 35 pages. Therefore, Xiaoming reads an average of 35 pages a day.
Wang Xiaoming read 30 pages on the first day of reading a book. According to the plot of the novel, the first few pages would usually be read on the first day because curiosity and interest would motivate the reader to start reading as soon as possible. The 30 pages might be the beginning of the story or an important part of the plot, which was why Wang Xiaoming finished reading the 30 pages on the first day. Wang Xiaoming would probably continue to read as the story developed. If this book was a classic novel, Wang Xiaoming would probably continue reading until he finished the story.
Xiao Dong read 3/5 of the book on the first day, which was 0.6 times the volume of the book. The next day, he read another 20 pages, which was equivalent to 1/5 of the entire book, which was 0.2 times the volume of the entire book. Therefore, the number of pages Little Dong had read was: The number of pages read = the volume of the book x the number of days read-the total number of pages = 06 × volume of the book × 1 - 02 × volume of the book = 02 × the volume of the book Since the total number of pages in the book did not change, the number of pages that Xiao Dong had read was 0.2 times that of the book.
Let the total number of pages of the book be x, then Xiaowang read 125% on the first day = 0125x 136 pages on the second day, so Xiaowang read a total of 0125x + 136 pages. The ratio of the remaining pages to the number of pages seen is 3:5, so the number of pages left is 0875x- 136, and the number of pages seen is 0875x- 136 + 0125x = 09x. According to the question, the ratio of the remaining pages to the number of pages seen is 3:5, so the equation can be written: 0875x - 136 = 3(09x) Solve the equation: 0125x = 192 x = 144 Therefore, the total number of pages in this book was 144.